C-03-Q204mediumsingle_mcq

With same condition, $x^3 + \dfrac{1}{x^3} = ?$

a $3$
b $2$
c $1$
d $0$

ব্যাখ্যা

From $x^2+\frac1{x^2}=1$ we get $\left(x+\frac1x\right)^2 = x^2+\frac1{x^2}+2 = 3$ , so $x+\frac1x=\sqrt3$ . Then $x^3+\frac1{x^3} = \left(x+\frac1x\right)^3 - 3\left(x+\frac1x\right) = 3\sqrt3 - 3\sqrt3 = 0$ .

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Algebraic Expressions — সব প্রশ্ন দেখুন (219টি) →

With same condition, $x^3 + \dfrac{1}{x^3} = ?$

3

2

1

0

With same condition, x3+1x3=?x^3 + \dfrac{1}{x^3} = ?x3+x31​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With same condition, x3+1x3=?x^3 + \dfrac{1}{x^3} = ?x3+x31​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With same condition, $x^3 + \dfrac{1}{x^3} = ?$

With same condition, $x^3 + \dfrac{1}{x^3} = ?$