C-03-Q207mediumsingle_mcqIf a2+b2=25a^2 + b^2 = 25a2+b2=25 and ab=12ab = 12ab=12, a2−b2=?a^2 - b^2 = ?a2−b2=?a±7\pm 7±7b777c111d494949ব্যাখ্যা(a2−b2)2=(a2+b2)2−4a2b2=252−4(12)2=625−576=49(a^2-b^2)^2 = (a^2+b^2)^2 - 4a^2b^2 = 25^2 - 4(12)^2 = 625 - 576 = 49(a2−b2)2=(a2+b2)2−4a2b2=252−4(12)2=625−576=49. Taking the square root gives a2−b2=±7a^2-b^2 = \pm 7a2−b2=±7, since both signs are possible.