C-03-Q213mediumsingle_mcqIf f(x)=x2−5x+6f(x) = x^2 - 5x + 6f(x)=x2−5x+6 and f(x)=0f(x) = 0f(x)=0, x=?x = ?x=?a2,32, 32,3b5,15, 15,1c−2,3-2, 3−2,3d1,−51, -51,−5ব্যাখ্যাSetting x2−5x+6=0x^2-5x+6=0x2−5x+6=0 and factoring gives (x−2)(x−3)=0(x-2)(x-3)=0(x−2)(x−3)=0. Hence the roots are x=2x = 2x=2 and x=3x = 3x=3.