C-03-Q203mediumsingle_mcqIf x4−x2+1=0x^4 - x^2 + 1 = 0x4−x2+1=0, x2+1x2=?x^2 + \dfrac{1}{x^2} = ?x2+x21=?a444b222c111d000ব্যাখ্যাDividing x4−x2+1=0x^4 - x^2 + 1 = 0x4−x2+1=0 throughout by x2x^2x2 gives x2−1+1x2=0x^2 - 1 + \dfrac{1}{x^2} = 0x2−1+x21=0. Rearranging yields x2+1x2=1x^2 + \dfrac{1}{x^2} = 1x2+x21=1.