Factorize $2x^3 - 4x^2 + 3x - 1$:

Since $x=1$ makes the expression $2-4+3-1=0$, $(x-1)$ is a factor. Dividing $2x^3-4x^2+3x-1$ by $(x-1)$ gives the quotient $2x^2-2x+1$, so the factorization is $(x-1)(2x^2-2x+1)$.