C-03-Q212mediumsingle_mcqIf x=2−3x = 2 - \sqrt{3}x=2−3, x2=?x^2 = ?x2=?a111b7−437 - 4\sqrt{3}7−43c2+32 + \sqrt{3}2+3d12+3\dfrac{1}{2+\sqrt{3}}2+31ব্যাখ্যাSquaring x=2−3x = 2-\sqrt3x=2−3 gives x2=22−2(2)(3)+(3)2=4−43+3=7−43x^2 = 2^2 - 2(2)(\sqrt3) + (\sqrt3)^2 = 4 - 4\sqrt3 + 3 = 7 - 4\sqrt3x2=22−2(2)(3)+(3)2=4−43+3=7−43.