C-09-Q196mediumsingle_mcqIf tan(3A)=3\tan(3A) = \sqrt{3}tan(3A)=3, then A=?A = ?A=?a15∘15^\circ15∘b20∘20^\circ20∘c30∘30^\circ30∘d45∘45^\circ45∘ব্যাখ্যাSince tan3A=3\tan 3A=\sqrt3tan3A=3, the basic solution is 3A=60∘3A=60^\circ3A=60∘. Dividing gives A=20∘A=20^\circA=20∘.