C-09-Q202mediumsingle_mcqIf secA=cosecA\sec A = \operatorname{cosec} AsecA=cosecA (acute AAA), then A=?A = ?A=?a30∘30^\circ30∘b45∘45^\circ45∘c60∘60^\circ60∘d90∘90^\circ90∘ব্যাখ্যাsecA=cosecA\sec A=\operatorname{cosec} AsecA=cosecA implies cosA=sinA\cos A=\sin AcosA=sinA, i.e. tanA=1\tan A=1tanA=1. The acute solution is A=45∘A=45^\circA=45∘.