C-09-Q200mediumsingle_mcqIf sinA=cosA\sin A = \cos AsinA=cosA (acute AAA), then A=?A = ?A=?a30∘30^\circ30∘b45∘45^\circ45∘c60∘60^\circ60∘d90∘90^\circ90∘ব্যাখ্যাDividing both sides by cosA\cos AcosA gives tanA=1\tan A=1tanA=1, whose acute solution is A=45∘A=45^\circA=45∘.