C-09-Q206mediumsingle_mcqIn the same triangle, sin(A+C)=?\sin(A + C) = ?sin(A+C)=?a000b12\dfrac{1}{2}21c111d−1-1−1ব্যাখ্যাSince A=60∘A=60^\circA=60∘ and C=30∘C=30^\circC=30∘, we have A+C=90∘A+C=90^\circA+C=90∘, and sin90∘=1\sin 90^\circ=1sin90∘=1.