C-09-Q083mediumsingle_mcqIn the same triangle, sinθ=?\sin\theta = ?sinθ=?a1213\dfrac{12}{13}1312b513\dfrac{5}{13}135c512\dfrac{5}{12}125d1312\dfrac{13}{12}1213ব্যাখ্যাFor θ=∠ABC\theta = \angle ABCθ=∠ABC, the opposite side is AC=5AC = 5AC=5 and the hypotenuse is AB=13AB = 13AB=13. Hence .