C-09-Q086mediumsingle_mcqtanθ+cotθ=?\tan\theta + \cot\theta = ?tanθ+cotθ=?asinθ⋅cosθ\sin\theta \cdot \cos\thetasinθ⋅cosθbsecθ⋅cosecθ\sec\theta \cdot \operatorname{cosec}\thetasecθ⋅cosecθc111d000ব্যাখ্যাWriting in terms of sine and cosine, tanθ+cotθ=sinθcosθ+cosθsinθ=sin2θ+cos2θsinθcosθ=1sinθcosθ\tan\theta + \cot\theta = \dfrac{\sin\theta}{\cos\theta} + \dfrac{\cos\theta}{\sin\theta} = \dfrac{\sin^2\theta + \cos^2\theta}{\sin\theta\cos\theta} = \dfrac{1}{\sin\theta\cos\theta}tanθ+cotθ=cosθsinθ+sinθcosθ=sinθcosθsin2θ+cos2θ=sinθcosθ1. This equals 1cosθ⋅1sinθ=secθ⋅cosecθ\dfrac{1}{\cos\theta}\cdot\dfrac{1}{\sin\theta} = \sec\theta\cdot\operatorname{cosec}\thetacosθ1⋅sinθ1=secθ⋅cosecθ.