C-09-Q085mediumsingle_mcqIn the same triangle, tanθ=?\tan\theta = ?tanθ=?a512\dfrac{5}{12}125b125\dfrac{12}{5}512c513\dfrac{5}{13}135d135\dfrac{13}{5}513ব্যাখ্যাWith the opposite side 555 and adjacent side 121212 (so the hypotenuse is 131313), tanθ=oppositeadjacent=512\tan\theta = \dfrac{\text{opposite}}{\text{adjacent}} = \dfrac{5}{12}tanθ=adjacentopposite=125.