C-08-Q034mediumsingle_mcq

Corollary 2 of Theorem 17 states that a straight line cannot intersect a circle in more than—

aone point
btwo points
cthree points
dfour points

ব্যাখ্যা

A straight line can cut a circle in at most two points; if it met the circle in three points, two of the resulting equal-radius arguments would force the points to coincide. So the maximum number of intersection points is two.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q035The converse stated in the Work box of Theorem 17 says: the perpendicular from the centre of a circle to a cho
C-08-Q036If is the midpoint of chord and is the centre, then holds for—
C-08-Q037From the centre , a perpendicular dropped on a chord of length cm meets the chord at distance—
C-08-Q038The Work box challenges the student to prove that the perpendicular from the centre—
C-08-Q039Theorem 18 states that all equal chords of a circle are—
C-08-Q040In Theorem 18, and are drawn—
C-08-Q041Because the perpendicular from the centre bisects the chord, equals—
C-08-Q042In the proof of Theorem 18, which congruence rule is used to show ?
C-08-Q043After , we conclude—
C-08-Q044The hypotenuse used in Theorem 18's RHS step is—

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