C-08-Q042mediumsingle_mcq

In the proof of Theorem 18, which congruence rule is used to show $\triangle OAE \cong \triangle OCF$ ?

aSSS
bSAS
cRHS
dAAS

ব্যাখ্যা

The two triangles each contain a right angle (the perpendicular from the centre to a chord), a common/equal hypotenuse (the radius), and an equal side, so the Right angle–Hypotenuse–Side (RHS) rule applies.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q043After , we conclude—
C-08-Q044The hypotenuse used in Theorem 18's RHS step is—
C-08-Q045In Theorem 18, because they are—
C-08-Q046If two chords of a circle are equal, then the perpendicular distances from the centre to those chords are—
C-08-Q047Theorem 19 states that chords equidistant from the centre of a circle are—
C-08-Q048Theorem 19 is the converse of—
C-08-Q049In Theorem 19, implies that—
C-08-Q050In Theorem 19's proof, is justified by which rule?
C-08-Q051From and the fact that perpendicular from centre bisects chord, we conclude—
C-08-Q052Corollary 3 (following Theorem 19) states that—

Circle — সব প্রশ্ন দেখুন (231টি) →

In the proof of Theorem 18, which congruence rule is used to show △OAE≅△OCF\triangle OAE \cong \triangle OCF△OAE≅△OCF?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the proof of Theorem 18, which congruence rule is used to show △OAE≅△OCF\triangle OAE \cong \triangle OCF△OAE≅△OCF?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In the proof of Theorem 18, which congruence rule is used to show $\triangle OAE \cong \triangle OCF$ ?

In the proof of Theorem 18, which congruence rule is used to show $\triangle OAE \cong \triangle OCF$ ?