C-08-Q044mediumsingle_mcq

The hypotenuse used in Theorem 18's RHS step is—

a $AE$
b $CF$
c $OA$ (or $OC$ ), the radius
d $EF$

ব্যাখ্যা

In an RHS comparison the hypotenuse is the side opposite the right angle; here that side is the radius $OA$ (equivalently $OC$ ), which is common to the configuration and equal in both triangles.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q045In Theorem 18, because they are—
C-08-Q046If two chords of a circle are equal, then the perpendicular distances from the centre to those chords are—
C-08-Q047Theorem 19 states that chords equidistant from the centre of a circle are—
C-08-Q048Theorem 19 is the converse of—
C-08-Q049In Theorem 19, implies that—
C-08-Q050In Theorem 19's proof, is justified by which rule?
C-08-Q051From and the fact that perpendicular from centre bisects chord, we conclude—
C-08-Q052Corollary 3 (following Theorem 19) states that—
C-08-Q053Of two chords of a circle, the one closer to the centre is—
C-08-Q054The greatest chord of a circle has length—

Circle — সব প্রশ্ন দেখুন (231টি) →