C-08-Q040mediumsingle_mcq

In Theorem 18, $OE$ and $OF$ are drawn—

aparallel to chords $AB$ and $CD$
bperpendicular to chords $AB$ and $CD$
cequal to chords $AB$ and $CD$
das tangents

ব্যাখ্যা

$OE$ and $OF$ are the perpendiculars from the centre to chords $AB$ and $CD$ , drawn so that their lengths measure each chord's distance from the centre. This perpendicular construction lets the equal chords be compared.

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q041Because the perpendicular from the centre bisects the chord, equals—
C-08-Q042In the proof of Theorem 18, which congruence rule is used to show ?
C-08-Q043After , we conclude—
C-08-Q044The hypotenuse used in Theorem 18's RHS step is—
C-08-Q045In Theorem 18, because they are—
C-08-Q046If two chords of a circle are equal, then the perpendicular distances from the centre to those chords are—
C-08-Q047Theorem 19 states that chords equidistant from the centre of a circle are—
C-08-Q048Theorem 19 is the converse of—
C-08-Q049In Theorem 19, implies that—
C-08-Q050In Theorem 19's proof, is justified by which rule?

Circle — সব প্রশ্ন দেখুন (231টি) →

In Theorem 18, $OE$ and $OF$ are drawn—

aparallel to chords

AB

and

CD

bperpendicular to chords

AB

and

CD

cequal to chords

AB

and

CD

das tangents

In Theorem 18, OEOEOE and OFOFOF are drawn—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Theorem 18, OEOEOE and OFOFOF are drawn—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Theorem 18, $OE$ and $OF$ are drawn—

In Theorem 18, $OE$ and $OF$ are drawn—