C-08-Q036: If $M$ is the midpoint of chord $AB$ and $O$ is the centre, then $OM \… | প্রশ্ন করি

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C-08-Q036mediumsingle_mcq

If $M$ is the midpoint of chord $AB$ and $O$ is the centre, then $OM \perp AB$ holds for—

aonly the diameter
bonly chords longer than the radius
cany chord other than the diameter
donly chords passing through $O$

ব্যাখ্যা

The line from the centre to the midpoint of a chord is perpendicular to that chord, a property that holds for any chord except the diameter (whose midpoint is the centre itself). Hence the answer is any chord other than the diameter.

36/231

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q037From the centre , a perpendicular dropped on a chord of length cm meets the chord at distance—
C-08-Q038The Work box challenges the student to prove that the perpendicular from the centre—
C-08-Q039Theorem 18 states that all equal chords of a circle are—
C-08-Q040In Theorem 18, and are drawn—
C-08-Q041Because the perpendicular from the centre bisects the chord, equals—
C-08-Q042In the proof of Theorem 18, which congruence rule is used to show ?
C-08-Q043After , we conclude—
C-08-Q044The hypotenuse used in Theorem 18's RHS step is—
C-08-Q045In Theorem 18, because they are—

C-08-Q046

If two chords of a circle are equal, then the perpendicular distances from the centre to those chords are—

Circle — সব প্রশ্ন দেখুন (231টি) →

If MMM is the midpoint of chord ABABAB and OOO is the centre, then OM⊥ABOM \perp ABOM⊥AB holds for—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

If $M$ is the midpoint of chord $AB$ and $O$ is the centre, then $OM \perp AB$ holds for—