C-09-Q216mediumsingle_mcq

With the same triangle and $\angle C = \theta$ , $\sin\theta + \cos\theta = ?$

a $\dfrac{17}{13}$
b $\dfrac{7}{13}$
c $\dfrac{12}{13}$
d $\dfrac{5}{13}$

ব্যাখ্যা

With hypotenuse $AC=13$ , for $\angle C=\theta$ we get $\sin\theta=\dfrac{AB}{AC}=\dfrac{5}{13}$ and $\cos\theta=\dfrac{BC}{AC}=\dfrac{12}{13}$ , so their sum is $\dfrac{17}{13}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-09-Q217For acute ,
C-09-Q207Given the same triangle, of the statements (i) , (ii) , (iii) , which are correct?
C-09-Q208In the same triangle,
C-09-Q209In the same triangle,
C-09-Q210With , , ( acute) and , then
C-09-Q211If (with , , acute), then
C-09-Q212
C-09-Q213In right with , and , then
C-09-Q214If , then
C-09-Q215In right with , and , then

Trigonometric Ratio — সব প্রশ্ন দেখুন (217টি) →

With the same triangle and $\angle C = \theta$ , $\sin\theta + \cos\theta = ?$

\dfrac{17}{13}

\dfrac{7}{13}

\dfrac{12}{13}

\dfrac{5}{13}

ব্যাখ্যা

With hypotenuse $AC=13$ , for $\angle C=\theta$ we get $\sin\theta=\dfrac{AB}{AC}=\dfrac{5}{13}$ and $\cos\theta=\dfrac{BC}{AC}=\dfrac{12}{13}$ , so their sum is $\dfrac{17}{13}$ .

With the same triangle and ∠C=θ\angle C = \theta∠C=θ, sin⁡θ+cos⁡θ=?\sin\theta + \cos\theta = ?sinθ+cosθ=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With the same triangle and ∠C=θ\angle C = \theta∠C=θ, sin⁡θ+cos⁡θ=?\sin\theta + \cos\theta = ?sinθ+cosθ=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With the same triangle and $\angle C = \theta$ , $\sin\theta + \cos\theta = ?$

With the same triangle and $\angle C = \theta$ , $\sin\theta + \cos\theta = ?$