C-09-Q216mediumsingle_mcqWith the same triangle and ∠C=θ\angle C = \theta∠C=θ, sinθ+cosθ=?\sin\theta + \cos\theta = ?sinθ+cosθ=?a1713\dfrac{17}{13}1317b713\dfrac{7}{13}ব্যাখ্যাWith hypotenuse AC=13AC=13AC=13, for ∠C=θ\angle C=\theta∠C=θ we get sinθ=ABAC=513\sin\theta=\dfrac{AB}{AC}=\dfrac{5}{13}sinθ= and , so their sum is .