C-09-Q210mediumsingle_mcqWith sinθ=p\sin\theta = psinθ=p, cosθ=q\cos\theta = qcosθ=q, tanθ=r\tan\theta = rtanθ=r (θ\thetaθ acute) and r=3−1r = \sqrt{3^{-1}}r=3−1, then θ=?\theta = ?θ=?a30∘30^\circ30∘b45∘45^\circ45∘c60∘60^\circ60∘d75∘75^\circ75∘ব্যাখ্যাSince tanθ=r=3−1=13\tan\theta=r=\sqrt{3^{-1}}=\dfrac{1}{\sqrt{3}}tanθ=r=3−1=31 and tan30∘=13\tan 30^\circ=\dfrac{1}{\sqrt3}tan30∘=3, the acute angle is θ=30∘\theta=30^\circθ=30∘.