C-09-Q215mediumsingle_mcqIn right △ABC\triangle ABC△ABC with ∠B=90∘\angle B = 90^\circ∠B=90∘, AB=5AB = 5AB=5 and BC=12BC = 12BC=12, then AC=?AC = ?AC=?a131313b171717c111111d141414ব্যাখ্যাBy the Pythagorean theorem the hypotenuse AC=AB2+BC2=52+122=169=13AC=\sqrt{AB^2+BC^2}=\sqrt{5^2+12^2}=\sqrt{169}=13AC=AB2+BC2=52+122=169=13.