C-09-Q101mediumsingle_mcq

$\dfrac{1}{\operatorname{cosec} A - 1} - \dfrac{1}{\operatorname{cosec} A + 1} = ?$

a $2\tan^2 A$
b $2\cot^2 A$
c $2\sec^2 A$
d $2\operatorname{cosec}^2 A$

ব্যাখ্যা

Combining gives $\dfrac{(\operatorname{cosec} A+1) - (\operatorname{cosec} A-1)}{\operatorname{cosec}^2 A - 1} = \dfrac{2}{\cot^2 A}$ . Since $\dfrac{1}{\cot^2 A} = \tan^2 A$ , this equals $2\tan^2 A$ .

এই অধ্যায়ের আরও প্রশ্ন

C-09-Q102
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C-09-Q111With as in the previous question and , then

Trigonometric Ratio — সব প্রশ্ন দেখুন (217টি) →

$\dfrac{1}{\operatorname{cosec} A - 1} - \dfrac{1}{\operatorname{cosec} A + 1} = ?$

2\tan^2 A

2\cot^2 A

2\sec^2 A

2\operatorname{cosec}^2 A

1cosec⁡A−1−1cosec⁡A+1=?\dfrac{1}{\operatorname{cosec} A - 1} - \dfrac{1}{\operatorname{cosec} A + 1} = ?cosecA−11​−cosecA+11​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

1cosec⁡A−1−1cosec⁡A+1=?\dfrac{1}{\operatorname{cosec} A - 1} - \dfrac{1}{\operatorname{cosec} A + 1} = ?cosecA−11​−cosecA+11​=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

$\dfrac{1}{\operatorname{cosec} A - 1} - \dfrac{1}{\operatorname{cosec} A + 1} = ?$

$\dfrac{1}{\operatorname{cosec} A - 1} - \dfrac{1}{\operatorname{cosec} A + 1} = ?$