C-09-Q100mediumsingle_mcq11+sinA+11−sinA=?\dfrac{1}{1 + \sin A} + \dfrac{1}{1 - \sin A} = ?1+sinA1+1−sinA1=?a2sec2A2\sec^2 A2sec2Ab2cosec2A2\operatorname{cosec}^2 A2cosecব্যাখ্যাAdding the fractions gives (1−sinA)+(1+sinA)(1+sinA)(1−sinA)=21−sin2A=2cos2A=2sec2A\dfrac{(1-\sin A)+(1+\sin A)}{(1+\sin A)(1-\sin A)} = \dfrac{2}{1 - \sin^2 A} = \dfrac{2}{\cos^2 A} = 2\sec^2 A(1+sinA)(1.