C-09-Q073mediumsingle_mcqWith the same data, sinθ=?\sin\theta = ?sinθ=?a2029\dfrac{20}{29}2920b2129\dfrac{21}{29}2921c2120\dfrac{21}{20}2021d2021\dfrac{20}{21}2120ব্যাখ্যাFor θ=∠ABC\theta = \angle ABCθ=∠ABC, the opposite side is AC=20AC = 20AC=20 and the hypotenuse is AB=29AB = 29AB=29. Thus sinθ=opphyp=2029\sin\theta = \dfrac{\text{opp}}{\text{hyp}} = \dfrac{20}{29}sinθ=hypopp=2920.