C-09-Q072mediumsingle_mcq

With the same data ( $\angle C = 90^\circ$ , $AB = 29$ , $BC = 21$ , $\angle ABC = \theta$ ), $\cos\theta = ?$

a $\dfrac{20}{29}$
b $\dfrac{21}{29}$
c $\dfrac{21}{20}$
d $\dfrac{20}{21}$

ব্যাখ্যা

For $\theta = \angle ABC$ , the adjacent side is $BC = 21$ and the hypotenuse is $AB = 29$ . Hence $\cos\theta = \dfrac{\text{adj}}{\text{hyp}} = \dfrac{21}{29}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-09-Q073With the same data,
C-09-Q074With the same data,
C-09-Q075If ,
C-09-Q076If , then
C-09-Q077If , then opposite adjacent
C-09-Q078If , hypotenuse (taking opposite , adjacent )
C-09-Q079If ,
C-09-Q080If ,
C-09-Q081In right with , , , . Then
C-09-Q082With , , , the hypotenuse is—

Trigonometric Ratio — সব প্রশ্ন দেখুন (217টি) →

With the same data ( $\angle C = 90^\circ$ , $AB = 29$ , $BC = 21$ , $\angle ABC = \theta$ ), $\cos\theta = ?$

\dfrac{20}{29}

\dfrac{21}{29}

\dfrac{21}{20}

\dfrac{20}{21}

ব্যাখ্যা

For $\theta = \angle ABC$ , the adjacent side is $BC = 21$ and the hypotenuse is $AB = 29$ . Hence $\cos\theta = \dfrac{\text{adj}}{\text{hyp}} = \dfrac{21}{29}$ .

With the same data (∠C=90∘\angle C = 90^\circ∠C=90∘, AB=29AB = 29AB=29, BC=21BC = 21BC=21, ∠ABC=θ\angle ABC = \theta∠ABC=θ), cos⁡θ=?\cos\theta = ?cosθ=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With the same data (∠C=90∘\angle C = 90^\circ∠C=90∘, AB=29AB = 29AB=29, BC=21BC = 21BC=21, ∠ABC=θ\angle ABC = \theta∠ABC=θ), cos⁡θ=?\cos\theta = ?cosθ=?

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With the same data ( $\angle C = 90^\circ$ , $AB = 29$ , $BC = 21$ , $\angle ABC = \theta$ ), $\cos\theta = ?$

With the same data ( $\angle C = 90^\circ$ , $AB = 29$ , $BC = 21$ , $\angle ABC = \theta$ ), $\cos\theta = ?$