C-09-Q065mediumsingle_mcqIf tanA=43\tan A = \dfrac{4}{3}tanA=34, cosecA=?\operatorname{cosec} A = ?cosecA=?a53\dfrac{5}{3}35b54\dfrac{5}{4}4ব্যাখ্যাWith tanA=43\tan A = \frac43tanA=34, take opposite =4=4=4, adjacent =3=3, so hypotenuse . Then .