C-09-Q069mediumsingle_mcqIf tanA=1\tan A = 1tanA=1, then sinA=?\sin A = ?sinA=?a111b12\dfrac{1}{\sqrt{2}}2ব্যাখ্যাtanA=1\tan A = 1tanA=1 corresponds to A=45∘A = 45^\circA=45∘. The sine of 45∘45^\circ45 is .