C-13-Q070mediumsingle_mcq(1+2+3+⋯+n)2=?\left(1 + 2 + 3 + \cdots + n\right)^{2} = ?(1+2+3+⋯+n)2=?a13+23+⋯+n31^{3} + 2^{3} + \cdots + n^{3}13+23+⋯+nব্যাখ্যাBy the cube-sum identity, (1+2+⋯+n)2=[n(n+1)2]2=13+23+⋯+n3\left(1+2+\cdots+n\right)^2=\left[\frac{n(n+1)}{2}\right]^2=1^3+2^3+\cdots+n^3(1+2+⋯+n)2=. The square of the sum of natural numbers equals the sum of their cubes.