C-13-Q075mediumsingle_mcqThe sum of the first nnn natural even numbers is —an(n+1)n(n + 1)n(n+1)bn2n^{2}n2cn(n+1)2\dfrac{n(n+1)}{2}2n(n+1)d2n2n2nব্যাখ্যাThe first nnn even numbers sum to 2+4+⋯+2n=2(1+2+⋯+n)=2⋅n(n+1)2=n(n+1)2+4+\cdots+2n=2(1+2+\cdots+n)=2\cdot\frac{n(n+1)}{2}=n(n+1)2+4+⋯+2n=2(1+2+⋯+n)=2⋅2n(n+1)=n(n+1).