C-13-Q077mediumsingle_mcq1+2+3+⋯+100=?1 + 2 + 3 + \cdots + 100 = ?1+2+3+⋯+100=?a500050005000b505050505050c495049504950d101001010010100ব্যাখ্যাApplying n(n+1)2\frac{n(n+1)}{2}2n(n+1) with n=100n=100n=100 gives 100×1012=5050\frac{100\times 101}{2}=50502100×101=5050. This is the classic sum of the first hundred natural numbers.