C-13-Q073: If the sum of the cubes of the first $n$ natural numbers is $441$, the… | প্রশ্ন করি

C-13-Q073mediumsingle_mcq

If the sum of the cubes of the first $n$ natural numbers is $441$ , the value of $n$ is —

Since $\left[\frac{n(n+1)}{2}\right]^2=441$ , taking the square root gives , so . This yields .

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এই অধ্যায়ের আরও প্রশ্ন

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9

441

\frac{n(n+1)}{2}=21

n(n+1)=42

n=6

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