C-04-Q095mediumsingle_mcq(xpxq)p+q−r⋅(xqxr)q+r−p⋅(xrxp)r+p−q=?\left(\dfrac{x^p}{x^q}\right)^{p+q-r} \cdot \left(\dfrac{x^q}{x^r}\right)^{q+r-p} \cdot \left(\dfrac{x^r}{x^p}\right)^{r+p-q} = ?(xqxp)p+q−r⋅(xrxq)q+r−p⋅(xpxr)r+p−q=?axxxb111cxpqrx^{pqr}xpqrd000ব্যাখ্যাEach base reduces to a power of xxx, and the sum of the three exponents (p−q)(p+q−r)+(q−r)(q+r−p)+(r−p)(r+p−q)(p-q)(p+q-r)+(q-r)(q+r-p)+(r-p)(r+p-q)(p−q)(p+q−r)+(q−r)(q+r−p)+(r−p)(r+p−q) equals 000, so the result is x0=1x^0=1x0=1.