C-04-Q097mediumsingle_mcqa1/2⋅a1/3⋅a1/6=?a^{1/2} \cdot a^{1/3} \cdot a^{1/6} = ?a1/2⋅a1/3⋅a1/6=?aaaaba1/11a^{1/11}a1/11ca2a^{2}a2da1/6a^{1/6}a1/6ব্যাখ্যাThe exponents add: 12+13+16=1\frac{1}{2}+\frac{1}{3}+\frac{1}{6}=121+31+61=1, so the product is a1=aa^1=aa1=a.