C-04-Q104mediumsingle_mcq

$2^{-3} = \dfrac{1}{8}$ in log form is—

a $\log_2 \dfrac{1}{8} = -3$

ব্যাখ্যা

Keeping the same base $2$ , the argument $\frac{1}{8}$ becomes the log's argument and the exponent $-3$ becomes its value. So $2^{- 3} =$ is written as .

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b

\log_2 \dfrac{1}{8} = 3

c

\log_{1/8} 2 = -3

d

\log_{-3} 2 = \dfrac{1}{8}

2^{- 3} = \frac{1}{8}

\log_2 \frac{1}{8} = -3

Exponents and Logarithms — সব প্রশ্ন দেখুন (240টি) →

2−3=182^{-3} = \dfrac{1}{8}2−3=81​ in log form is—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

$2^{-3} = \dfrac{1}{8}$ in log form is—