C-04-Q092mediumsingle_mcqSolve 2x+21−x=32^x + 2^{1-x} = 32x+21−x=3:ax=0x = 0x=0 or x=1x = 1x=1bx=2x = 2x=2 or x=−1x = -1x=−1cx=−1x = -1x=−1 or x=0x = 0x=0dx=1x = 1x=1 onlyব্যাখ্যাLet t=2xt=2^xt=2x; then t+2t=3t+\frac{2}{t}=3t+t2=3 leads to t2−3t+2=0t^2-3t+2=0t2−3t+2=0, so t=1t=1t=1 or t=2t=2t=2, giving x=0x=0x=0 or x=1x=1x=1.