C-10-Q047mediumsingle_mcq

With $AB$ the height of a tower, $BC=75$ m the horizontal distance, and $\angle ACB = 30^\circ$ , the equation $\tan 30^\circ$ equals—

a $\dfrac{AB}{BC}$
b $\dfrac{BC}{AB}$
c $\dfrac{AC}{AB}$
d $\dfrac{AC}{BC}$

ব্যাখ্যা

In right triangle $ABC$ , the tangent of $\angle ACB$ equals the side opposite the angle ( $AB$ ) over the side adjacent to it ( $BC$ ). Hence $\tan 30^\circ = \dfrac{AB}{BC}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q048Therefore the height satisfies—
C-10-Q049Numerically equals—
C-10-Q050After rationalizing, becomes—
C-10-Q051The approximate height of the tower in Example 1 is—
C-10-Q052To rationalize , the numerator and denominator are multiplied by—
C-10-Q053In Example 2, with tree m, foot distance , and , equals—
C-10-Q054The distance satisfies—
C-10-Q055simplifies to—
C-10-Q056The approximate ground distance of the point in Example 2 is—
C-10-Q057The relation tells us that the side opposite the angle is times the—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

With $AB$ the height of a tower, $BC=75$ m the horizontal distance, and $\angle ACB = 30^\circ$ , the equation $\tan 30^\circ$ equals—

\dfrac{AB}{BC}

\dfrac{BC}{AB}

\dfrac{AC}{AB}

\dfrac{AC}{BC}

ব্যাখ্যা

In right triangle $ABC$ , the tangent of $\angle ACB$ equals the side opposite the angle ( $AB$ ) over the side adjacent to it ( $BC$ ). Hence $\tan 30^\circ = \dfrac{AB}{BC}$ .

With ABABAB the height of a tower, BC=75BC=75BC=75 m the horizontal distance, and ∠ACB=30∘\angle ACB = 30^\circ∠ACB=30∘, the equation tan⁡30∘\tan 30^\circtan30∘ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With ABABAB the height of a tower, BC=75BC=75BC=75 m the horizontal distance, and ∠ACB=30∘\angle ACB = 30^\circ∠ACB=30∘, the equation tan⁡30∘\tan 30^\circtan30∘ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

With $AB$ the height of a tower, $BC=75$ m the horizontal distance, and $\angle ACB = 30^\circ$ , the equation $\tan 30^\circ$ equals—

With $AB$ the height of a tower, $BC=75$ m the horizontal distance, and $\angle ACB = 30^\circ$ , the equation $\tan 30^\circ$ equals—