C-10-Q053mediumsingle_mcq

In Example 2, with tree $AB=105$ m, foot distance $BC=x$ , and $\angle ACB=60^\circ$ , $\tan 60^\circ$ equals—

a $\dfrac{BC}{AB}$
b $\dfrac{AB}{BC}$

ব্যাখ্যা

Tangent of an angle equals the opposite side over the adjacent side. Here $AB$ (height) is opposite $\angle ACB$ and $BC$ is adjacent, so $\tan 60^\circ = \dfrac{AB}{BC}$ .

53/160

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q054The distance satisfies—
C-10-Q055simplifies to—
C-10-Q056The approximate ground distance of the point in Example 2 is—
C-10-Q057The relation tells us that the side opposite the angle is times the—
C-10-Q058With the same height m, if the elevation were instead of , the foot distance would be—
C-10-Q059A ladder of length m leans against a wall making with the ground; with m and wall height , equals—
C-10-Q060Therefore the wall height equals—
C-10-Q061in surd form equals—
C-10-Q062The approximate wall height in Example 3 is—

BCAB

\dfrac{AB}{AC}

\dfrac{BC}{AC}

∘

BCAB

C-10-Q063The horizontal distance from the foot of the wall to the foot of the ladder is—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

In Example 2, with tree AB=105AB=105AB=105 m, foot distance BC=xBC=xBC=x, and ∠ACB=60∘\angle ACB=60^\circ∠ACB=60∘, tan⁡60∘\tan 60^\circtan60∘ equals—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Example 2, with tree $AB=105$ m, foot distance $BC=x$ , and $\angle ACB=60^\circ$ , $\tan 60^\circ$ equals—