C-10-Q057mediumsingle_mcq

The relation $\tan 60^\circ = \sqrt{3}$ tells us that the side opposite the $60^\circ$ angle is $\sqrt{3}$ times the—

aadjacent side
bhypotenuse
copposite side itself
dperimeter

ব্যাখ্যা

Because $\tan 60^\circ = \dfrac{\text{opposite}}{\text{adjacent}} = \sqrt{3}$ , the side opposite the $60^\circ$ angle is $\sqrt{3}$ times the adjacent side. This is the defining ratio of the tangent.

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q058With the same height m, if the elevation were instead of , the foot distance would be—
C-10-Q059A ladder of length m leans against a wall making with the ground; with m and wall height , equals—
C-10-Q060Therefore the wall height equals—
C-10-Q061in surd form equals—
C-10-Q062The approximate wall height in Example 3 is—
C-10-Q063The horizontal distance from the foot of the wall to the foot of the ladder is—
C-10-Q064In a –– right triangle, the two legs are—
C-10-Q065The stick contacts the tree at m above the ground; the depression angle at the contact is . By alternate angle
C-10-Q066From right with stick as hypotenuse, equals—
C-10-Q067Therefore equals—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

The relation $\tan 60^\circ = \sqrt{3}$ tells us that the side opposite the $60^\circ$ angle is $\sqrt{3}$ times the—

aadjacent side

bhypotenuse

copposite side itself

dperimeter

The relation tan⁡60∘=3\tan 60^\circ = \sqrt{3}tan60∘=3​ tells us that the side opposite the 60∘60^\circ60∘ angle is 3\sqrt{3}3​ times the—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The relation tan⁡60∘=3\tan 60^\circ = \sqrt{3}tan60∘=3​ tells us that the side opposite the 60∘60^\circ60∘ angle is 3\sqrt{3}3​ times the—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

The relation $\tan 60^\circ = \sqrt{3}$ tells us that the side opposite the $60^\circ$ angle is $\sqrt{3}$ times the—

The relation $\tan 60^\circ = \sqrt{3}$ tells us that the side opposite the $60^\circ$ angle is $\sqrt{3}$ times the—