C-10-Q052mediumsingle_mcq

To rationalize $\dfrac{75}{\sqrt{3}}$ , the numerator and denominator are multiplied by—

a $3$
b $\sqrt{3}$
c $\sqrt{2}$
d $\dfrac{1}{\sqrt{3}}$

ব্যাখ্যা

Multiplying numerator and denominator by $\sqrt{3}$ removes the radical from the denominator, since $\sqrt{3}\times\sqrt{3}=3$ . This gives $\dfrac{75\sqrt{3}}{3}=25\sqrt{3}$ .

এই অধ্যায়ের আরও প্রশ্ন

C-10-Q053In Example 2, with tree m, foot distance , and , equals—
C-10-Q054The distance satisfies—
C-10-Q055simplifies to—
C-10-Q056The approximate ground distance of the point in Example 2 is—
C-10-Q057The relation tells us that the side opposite the angle is times the—
C-10-Q058With the same height m, if the elevation were instead of , the foot distance would be—
C-10-Q059A ladder of length m leans against a wall making with the ground; with m and wall height , equals—
C-10-Q060Therefore the wall height equals—
C-10-Q061in surd form equals—
C-10-Q062The approximate wall height in Example 3 is—

Chapter 10: Distance and Elevation — সব প্রশ্ন দেখুন (160টি) →

To rationalize $\dfrac{75}{\sqrt{3}}$ , the numerator and denominator are multiplied by—

3

\sqrt{3}

\sqrt{2}

\dfrac{1}{\sqrt{3}}

ব্যাখ্যা

Multiplying numerator and denominator by $\sqrt{3}$ removes the radical from the denominator, since $\sqrt{3}\times\sqrt{3}=3$ . This gives $\dfrac{75\sqrt{3}}{3}=25\sqrt{3}$ .

To rationalize 753\dfrac{75}{\sqrt{3}}3​75​, the numerator and denominator are multiplied by—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

To rationalize 753\dfrac{75}{\sqrt{3}}3​75​, the numerator and denominator are multiplied by—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

To rationalize $\dfrac{75}{\sqrt{3}}$ , the numerator and denominator are multiplied by—

To rationalize $\dfrac{75}{\sqrt{3}}$ , the numerator and denominator are multiplied by—