C-08-Q049mediumsingle_mcq

In Theorem 19, $OE = OF$ implies that—

athe chords $AB$ and $CD$ are equal
bthe chords are perpendicular
cthe chords are parallel
done chord is a tangent

ব্যাখ্যা

$OE$ and $OF$ are the perpendicular distances from the centre to chords $AB$ and $CD$ ; their equality means the chords are equidistant, which forces $AB = CD$ .

এই অধ্যায়ের আরও প্রশ্ন

C-08-Q050In Theorem 19's proof, is justified by which rule?
C-08-Q051From and the fact that perpendicular from centre bisects chord, we conclude—
C-08-Q052Corollary 3 (following Theorem 19) states that—
C-08-Q053Of two chords of a circle, the one closer to the centre is—
C-08-Q054The greatest chord of a circle has length—
C-08-Q055The straight line joining the midpoints of two parallel chords of a circle—
C-08-Q056If two chords and of a circle subtend equal angles with the radius through , then—
C-08-Q057If a circle passes through the vertices of a right-angled triangle, then the centre of the circle is the—
C-08-Q058In two concentric circles a chord of the outer circle meets the inner circle at and . Then—
C-08-Q059If two equal chords of a circle intersect, the segments of one chord—

Circle — সব প্রশ্ন দেখুন (231টি) →

In Theorem 19, $OE = OF$ implies that—

athe chords

AB

and

CD

are equal

bthe chords are perpendicular

cthe chords are parallel

done chord is a tangent

ব্যাখ্যা

$OE$ and $OF$ are the perpendicular distances from the centre to chords $AB$ and $CD$ ; their equality means the chords are equidistant, which forces $AB = CD$ .

In Theorem 19, OE=OFOE = OFOE=OF implies that—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Theorem 19, OE=OFOE = OFOE=OF implies that—

ব্যাখ্যা

এই অধ্যায়ের আরও প্রশ্ন

In Theorem 19, $OE = OF$ implies that—

In Theorem 19, $OE = OF$ implies that—