C-03-Q219mediumsingle_mcqIf f(x)=x2−4x+4f(x) = x^2 - 4x + 4f(x)=x2−4x+4, f(2)=?f(2) = ?f(2)=?a444b222c111d000ব্যাখ্যাSubstituting x=2x=2x=2: f(2)=22−4(2)+4=4−8+4=0f(2) = 2^2 - 4(2) + 4 = 4 - 8 + 4 = 0f(2)=22−4(2)+4=4−8+4=0. (Note x2−4x+4=(x−2)2x^2-4x+4=(x-2)^2x2−4x+4=(x−2)2, which is zero at x=2x=2x=2.)