C-03-Q058mediumsingle_mcqIf a+b+c=6a+b+c=6a+b+c=6 and a2+b2+c2=14a^2+b^2+c^2=14a2+b2+c2=14, (a−b)2+(b−c)2+(c−a)2=?(a-b)^2+(b-c)^2+(c-a)^2 = ?(a−b)2+(b−c)2+(c−a)2=?a666b141414c363636d222222ব্যাখ্যাThe sum equals 2(a2+b2+c2)−2(ab+bc+ca)2(a^2+b^2+c^2)-2(ab+bc+ca)2(a2+b2+c2)−2(ab+bc+ca). Since ab+bc+ca=62−142=11ab+bc+ca=\frac{6^2-14}{2}=11ab+bc+ca=262−14=11, the value is 2(14)−2(11)=28−22=62(14)-2(11)=28-22=62(14)−2(11)=28−22=6.