C-03-Q062mediumsingle_mcqIf a4+a2b2+b4=8a^4 + a^2 b^2 + b^4 = 8a4+a2b2+b4=8 and a2+ab+b2=4a^2 + ab + b^2 = 4a2+ab+b2=4, a2+b2=?a^2 + b^2 = ?a2+b2=?a333b444c555d66ব্যাখ্যাSince a4+a2b2+b4=(a2+ab+b2)(a2−ab+b2)a^4+a^2b^2+b^4=(a^2+ab+b^2)(a^2-ab+b^2)a4+a2b2, dividing by gives . Adding to this gives , so .