C-03-Q062mediumsingle_mcqIf a4+a2b2+b4=8a^4 + a^2 b^2 + b^4 = 8a4+a2b2+b4=8 and a2+ab+b2=4a^2 + ab + b^2 = 4a2+ab+b2=4, a2+b2=?a^2 + b^2 = ?a2+b2=?a333b444c555d666ব্যাখ্যাSince a4+a2b2+b4=(a2+ab+b2)(a2−ab+b2)a^4+a^2b^2+b^4=(a^2+ab+b^2)(a^2-ab+b^2)a4+a2b2+b4=(a2+ab+b2)(a2−ab+b2), dividing 888 by 444 gives a2−ab+b2=2a^2-ab+b^2=2a2−ab+b2=2. Adding a2+ab+b2=4a^2+ab+b^2=4a2+ab+b2=4 to this gives 2(a2+b2)=62(a^2+b^2)=62(a2+b2)=6, so a2+b2=3a^2+b^2=3a2+b2=3.