C-09-Q143mediumsingle_mcqcos(90∘−θ)=?\cos(90^\circ - \theta) = ?cos(90∘−θ)=?asinθ\sin\thetasinθbcosθ\cos\thetacosθctanθ\tan\thetatanθdcotθ\cot\thetacotθব্যাখ্যাBy the complementary-angle identity, the cosine of an angle equals the sine of its complement, so cos(90∘−θ)=sinθ\cos(90^\circ - \theta) = \sin\thetacos(90∘−θ)=sinθ.