C-09-Q153mediumsingle_mcqtan0∘=?\tan 0^\circ = ?tan0∘=?a000b111c∞\infty∞dundefinedব্যাখ্যাSince tanθ=sinθcosθ=01=0\tan\theta=\dfrac{\sin\theta}{\cos\theta}=\dfrac{0}{1}=0tanθ=cosθsinθ=10=0 at 0∘0^\circ0∘, we get tan0∘=0\tan 0^\circ=0tan0∘=0.