C-09-Q126mediumsingle_mcqsin60∘=?\sin 60^\circ = ?sin60∘=?a12\dfrac{1}{2}21b12\dfrac{1}{\sqrt{2}}21c32\dfrac{\sqrt{3}}{2}23d111ব্যাখ্যাFrom the standard 30∘30^\circ30∘–60∘60^\circ60∘–90∘90^\circ90∘ triangle, the side opposite has ratio to the hypotenuse, giving .