C-09-Q133mediumsingle_mcqWith PM=OM=aPM = OM = aPM=OM=a, the hypotenuse OP=?OP = ?OP=?aaaaba2a\sqrt{2}a2c2a2a2ada3a\sqrt{3}a3ব্যাখ্যাBy the Pythagorean theorem, OP=PM2+OM2=a2+a2=2a2=a2OP = \sqrt{PM^2 + OM^2} = \sqrt{a^2 + a^2} = \sqrt{2a^2} = a\sqrt{2}OP=PM2+OM2=a2+a2=2a2=a2.