C-09-Q125mediumsingle_mcqsec30∘=?\sec 30^\circ = ?sec30∘=?a222b23\dfrac{2}{\sqrt{3}}32c2\sqrt{2}2d3\sqrt{3}3ব্যাখ্যাSince cos30∘=32\cos 30^\circ = \dfrac{\sqrt{3}}{2}cos30∘=23 and secant is its reciprocal, sec30∘=1cos30∘=23\sec 30^\circ = \dfrac{1}{\cos 30^\circ} = \dfrac{2}{\sqrt{3}}sec30∘=cos30∘1=32.