C-09-Q122mediumsingle_mcqtan30∘=?\tan 30^\circ = ?tan30∘=?a111b3\sqrt{3}3c13\dfrac{1}{\sqrt{3}}31d12\dfrac{1}{2}21ব্যাখ্যাtan30∘=sin30∘cos30∘=1/23/2=13\tan30^\circ=\dfrac{\sin30^\circ}{\cos30^\circ}=\dfrac{1/2}{\sqrt3/2}=\dfrac{1}{\sqrt3}tan30∘=cos30∘sin30∘=3/21/2=31, the standard value.