C-09-Q036mediumsingle_mcqsecθ=hypotenuse?\sec\theta = \dfrac{\text{hypotenuse}}{?}secθ=?hypotenuseaopposite sidebadjacent sidechypotenusedtangentব্যাখ্যাSince secθ=1cosθ\sec\theta=\dfrac{1}{\cos\theta}secθ=cosθ1 and cosθ=adjacenthypotenuse\cos\theta=\dfrac{\text{adjacent}}{\text{hypotenuse}}cosθ, the reciprocal gives . The denominator is the adjacent side.